3079 Find the Sum of Encrypted Integers

Fairly straightforward, the problem wants us to find the sum of the array elements but before calculating, the elements must be “encrypted.” As per their definition, a number is encrypted if all the digits in the number are replaced by the maximum digit in that number.

Code:

Python3

class Solution:
    def sumOfEncryptedInt(self, nums: List[int]) -> int:
        ret = 0
 
        for n in nums:
            ret += int(max(str(n)) * len(str(n)))
 
        return ret

Big O Analysis

• Runtime The runtime complexity here is O(N * M) where N = length of list nums and M = length of number nums[i].
• Memory Constant space! Since we don’t use any extra data structure.

— A

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