1290 Convert Binary Number in a Linked List to Integer

Intuition

The process of converting a binary string/number to an integer with base 10 is a recursive sub-process and so in a linked list.

So we aim at designing a recursive function that adds up to a integer by raising 2 to the current list node value if it’s 1 else 0.

We also have a size function that gives us the total size of the linked list.

Code

Python3

class Solution:
    def getDecimalValue(self, head: ListNode, length = 0) -> int:
        n = self.size(head)
 
        def count(node, length=0):
            if not node:
                return 0
 
            return count(node.next, length + 1) + (pow(2, n - length - 1) if node.val == 1 else 0)
 
        return count(head)
 
    def size(self, head):
        if not head: return 0
 
        return 1 + self.size(head.next)

Big O Analysis

• Runtime

  The runtime complexity here is $O(N)$ since we would be processing each node of the list atleast once.

• Memory

  The memory usage is $O(N)$ since we are doing recursion so that’s one function call in the stack memory for every node.

— A

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